document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27211>Question 27211</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14796 by </B><A HREF=/tutors/aboutme.mpl?userid=JayJay_T><B>JayJay_T(6)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JayJay_T><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A point defined as (-2, Y) implicates a given x-value as being '-2'.<BR>\n" );
document.write( "All you have to do is fill it in the equation:\r<BR>\n" );
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document.write( "3x - 2y = -18\r<BR>\n" );
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document.write( "if x = -2\r<BR>\n" );
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document.write( "-6 - 2y = -18<BR>\n" );
document.write( "-2y = -18 + 6<BR>\n" );
document.write( "-2y = -12\r<BR>\n" );
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document.write( "y = -12/-2\r<BR>\n" );
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document.write( "=> y = 6 </SPAN>\n" );
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