document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27164>Question 27164</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is four less than three times another. if their sum is increased by five, the results is tweny-five. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14795 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14795\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= one number;<BR>\n" );
document.write( "so, 3x-4= other number<BR>\n" );
document.write( "then;<BR>\n" );
document.write( "x+3x-4+5=25<BR>\n" );
document.write( "Now solve;<BR>\n" );
document.write( "4x+1=25<BR>\n" );
document.write( "4x=25<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "Now that we now x, we can figure out the other;<BR>\n" );
document.write( "3(6)-4=14<BR>\n" );
document.write( "so, one number is 6, the other is 14<BR>\n" );
document.write( "Hope you understand<BR>\n" );
document.write( "=) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );