document.write( "Question 197302: The length of a rectangle is 2 more than three times the width. If the perimeter is 92 cm, find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #147939 by anantha(86)![]() ![]() ![]() You can put this solution on YOUR website! sol: \n" ); document.write( "let the width be x \n" ); document.write( "three times the fwidth=3x \n" ); document.write( "length=2 more than 3 times the width \n" ); document.write( "length=2+3x \n" ); document.write( "perimeter of the rectangle=2(length+width) \n" ); document.write( " =2(2+3x+x) \n" ); document.write( " =2(2+4x) \n" ); document.write( " =2*2+2*4x \n" ); document.write( " =4+8x \n" ); document.write( "according to the problem perimeter of the rectangle=92cm \n" ); document.write( " 4+8x=92 \n" ); document.write( "subtract 4 on both sides \n" ); document.write( "4+8x-4=92-4 \n" ); document.write( "8x=88 \n" ); document.write( "dividing by 8 on both sides \n" ); document.write( "8x/8=88/8 \n" ); document.write( "x=11cm \n" ); document.write( "width=11cm \n" ); document.write( "length=2+3x \n" ); document.write( " =2+3*11 \n" ); document.write( " =2+33 \n" ); document.write( " =35 \n" ); document.write( "length=35cm \n" ); document.write( " |