document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=197289>Question 197289</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that twice the smallest increased by the largest is 128.<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147925 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find three consecutive integers such that twice the smallest increased by the largest is 128.<BR>\n" );
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document.write( "1st: x-1<BR>\n" );
document.write( "2nd: x<BR>\n" );
document.write( "3rd: x+1<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "2(x-1)+ (x+1) = 128<BR>\n" );
document.write( "2x-2 + x + 1 = 128<BR>\n" );
document.write( "3x = 129<BR>\n" );
document.write( "x = 43<BR>\n" );
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document.write( "1st = x-1 = 42<BR>\n" );
document.write( "2nd = x = 43<BR>\n" );
document.write( "3rd = x+1 = 44<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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