document.write( "Question 27194: A moterboat can go 8 miles downstream in 20 mins. It takes 30 mins for this boat to go back upstream the same 8 miles. Find the speed of the current. I know how to set everything up except for the rate. PLEASE HELP!!!! \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( " Thank You,
\n" );
document.write( " Stacy \n" );
document.write( "
Algebra.Com's Answer #14784 by Paul(988) ![]() You can put this solution on YOUR website! 20 minutes = 1/3 hours. \n" ); document.write( "30 minutes = 1/2 hours. \n" ); document.write( "Let the speed of the boat be y. \n" ); document.write( "Let the speed of the current be x.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x-y=16 \n" ); document.write( "y=16+x (subsitution)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x+y)/2=8 \n" ); document.write( "x+y=24 (subsitue for y) \n" ); document.write( "x+(16+x)=24 \n" ); document.write( "x+16+x=24 \n" ); document.write( "2x=8 \n" ); document.write( "x=4\r \n" ); document.write( "\n" ); document.write( "y=16+4 \n" ); document.write( "y=20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, the speed of the boat is 20mph and the speed of the current is 4mph.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |