document.write( "Question 27194: A moterboat can go 8 miles downstream in 20 mins. It takes 30 mins for this boat to go back upstream the same 8 miles. Find the speed of the current. I know how to set everything up except for the rate. PLEASE HELP!!!! \r
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\n" ); document.write( "\n" ); document.write( " Thank You,
\n" ); document.write( " Stacy
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Algebra.Com's Answer #14784 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
20 minutes = 1/3 hours.
\n" ); document.write( "30 minutes = 1/2 hours.
\n" ); document.write( "Let the speed of the boat be y.
\n" ); document.write( "Let the speed of the current be x.\r
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\n" ); document.write( "\n" ); document.write( "\"8%2F%28x-y%29%2F3=8%2F%28x%2By%29%2F2\"
\n" ); document.write( "\"%28x%2By%29%2F2=8\" ---> solve for y
\n" ); document.write( "x-y=16
\n" ); document.write( "y=16+x (subsitution)\r
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\n" ); document.write( "\n" ); document.write( "(x+y)/2=8
\n" ); document.write( "x+y=24 (subsitue for y)
\n" ); document.write( "x+(16+x)=24
\n" ); document.write( "x+16+x=24
\n" ); document.write( "2x=8
\n" ); document.write( "x=4\r
\n" ); document.write( "\n" ); document.write( "y=16+4
\n" ); document.write( "y=20\r
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\n" ); document.write( "\n" ); document.write( "Hence, the speed of the boat is 20mph and the speed of the current is 4mph.\r
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