document.write( "Question 27188: two integers have a sum of 29. Three times the larger is 3 more than four times the smaller. I set it up like this: 3x + 4(x+3)=29 but i did not get the correct answer \n" ); document.write( "
Algebra.Com's Answer #14776 by Paul(988)\"\" \"About 
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Let the first integer be x
\n" ); document.write( "Let the second integer be y
\n" ); document.write( "x+y=29 Solve for y
\n" ); document.write( "y=29-x (subsitution)\r
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\n" ); document.write( "\n" ); document.write( "3x=3+4y
\n" ); document.write( "Subsitute for y
\n" ); document.write( "3x=3+4(29-x)
\n" ); document.write( "3x=3+116-4x
\n" ); document.write( "7x=119
\n" ); document.write( "x=17\r
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\n" ); document.write( "\n" ); document.write( "y=29-17
\n" ); document.write( "y=12\r
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\n" ); document.write( "\n" ); document.write( "Hence, the two integers are 17 and 12.
\n" ); document.write( "Paul.\r
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