document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196982>Question 196982</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2000, the population of Town A was 9,400 and the population of Town B was 7,600.  Since then, each year the population of Town A has decreased by 100 and the population of Town B has increased by 100.  Assuming that in each case the rate continues, in what year will the two populations be equal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147751 by </B><A HREF=/tutors/aboutme.mpl?userid=briannadee><B>briannadee(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=briannadee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If town A has a population of 9,400 and town B had a population of 7,600 in year 2000 and town A decreases and town B increases, then just keep adding and subtracting them to get the answer.\r<BR>\n" );
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document.write( "TOWN A-     TOWN B+         <BR>\n" );
document.write( "9,400 2000 7,600<BR>\n" );
document.write( "9,300 2001 7,700<BR>\n" );
document.write( "9,200 2002 7,800<BR>\n" );
document.write( "9,100 2003 7,900<BR>\n" );
document.write( "9,000 2004 8,000<BR>\n" );
document.write( "8,900 2005 8,100<BR>\n" );
document.write( "8,800 2006 8,200<BR>\n" );
document.write( "8,700 2007 8,300<BR>\n" );
document.write( "8,600 2008 8,400<BR>\n" );
document.write( "8,500 2009 8,500\r<BR>\n" );
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document.write( "So as you can see the year 2009 is when the both have to same population. </SPAN>\n" );
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