document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196646>Question 196646</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log (subscript 2) (x^2+8) = log (subscript 2)x +log (subscript 2)6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147707 by </B><A HREF=/tutors/aboutme.mpl?userid=chiefman><B>chiefman(11)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chiefman><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chiefman><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  for RHS factoring out log(base2) we have<BR>\n" );
document.write( " log(base2)[6x] since loga+logb=log(ab)<BR>\n" );
document.write( " equating LHS and RHS we have<BR>\n" );
document.write( " log(base2)[x^2+8]=log(base2)[6x]<BR>\n" );
document.write( " cancelling log(base2)since it is commom on both sides<BR>\n" );
document.write( " x^2+8=6x<BR>\n" );
document.write( " x^2-6x+8=0 a quadratic equation<BR>\n" );
document.write( " solving for x we get <BR>\n" );
document.write( " x=4or2 </SPAN>\n" );
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