document.write( "Question 196991: For all a, (3a+4)(4a-3)= \n" ); document.write( "
Algebra.Com's Answer #147690 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"%283a%2B4%29%284a-3%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283a%29%2B4%29%28highlight%284a%29-3%29\" Multiply the First terms:\"%283a%29%284a%29=12a%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283a%29%2B4%29%284a%2Bhighlight%28-3%29%29\" Multiply the Outer terms:\"%283a%29%28-3%29=-9a\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%2Bhighlight%284%29%29%28highlight%284a%29-3%29\" Multiply the Inner terms:\"%284%29%284a%29=16a\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283a%2Bhighlight%284%29%29%284a%2Bhighlight%28-3%29%29\" Multiply the Last terms:\"%284%29%28-3%29=-12\".\r
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\n" ); document.write( "\n" ); document.write( "So we have the terms: \"12a%5E2\", \"-9a\", \"16a\", and \"-12\" \r
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\n" ); document.write( "\n" ); document.write( "\"12a%5E2-9a%2B16a-12\" Now add every term listed above to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"12a%5E2%2B7a-12\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"%283a%2B4%29%284a-3%29\" FOILs to \"12a%5E2%2B7a-12\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%283a%2B4%29%284a-3%29=12a%5E2%2B7a-12\".
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