document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27163>Question 27163</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is four less than three times another. if their sum is increased by five,the results is twenty-five. find he numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14766 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First number = x<BR>\n" );
document.write( "Second number  = 3x-4<BR>\n" );
document.write( "Increased by 5:<BR>\n" );
document.write( "(x)+(3x-4)+5=25<BR>\n" );
document.write( "4x+1=25<BR>\n" );
document.write( "4x=24<BR>\n" );
document.write( "x=6 (first number)\r<BR>\n" );
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document.write( "3(6)-4=14 (second number)\r<BR>\n" );
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document.write( "Hence, the two numbers are 6 and 14.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );