document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196869>Question 196869</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147641 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let  x=  1st  side<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let  .25x  =  2nd  side<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let  x+4  =  3  rd  side<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Perimeter  =49 = (x) + (.25x) +( x+4) = 2.25 x +4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "45 = 2.25 x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( ".<BR>\n" );
document.write( "sides  = 20,  5,  24<BR>\n" );
document.write( ".<BR>\n" );
document.write( "checking  per  =  49  ,,,,ok </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );