document.write( "Question 196896: I have a few problems I'm struggling with:\r
\n" ); document.write( "\n" ); document.write( "1: x^2 - 3x = -10 (directions say use quadratic formula, use radicals as needed).\r
\n" ); document.write( "\n" ); document.write( "2: (x+12)(x-8)(x+8)>0 (directions say to use one equality or compount equality)\r
\n" ); document.write( "\n" ); document.write( "3: 2x^2 - 5x +1 (evaluate polynomial for x= -4\r
\n" ); document.write( "\n" ); document.write( "4: (9x^8 - 3)(x^9 - 3) (use FOIL to find product)
\n" ); document.write( "I thank you in advance for time spent in helping with these problems
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Algebra.Com's Answer #147630 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
# 1\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x=-10\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-3x%2B10=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"Ax%5E2%2BBx%2BC\" where \"A=1\", \"B=-3\", and \"C=10\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-3%29+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%2810%29+%29%29%2F%282%281%29%29\" Plug in \"A=1\", \"B=-3\", and \"C=10\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+%28-3%29%5E2-4%281%29%2810%29+%29%29%2F%282%281%29%29\" Negate \"-3\" to get \"3\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-4%281%29%2810%29+%29%29%2F%282%281%29%29\" Square \"-3\" to get \"9\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+9-40+%29%29%2F%282%281%29%29\" Multiply \"4%281%29%2810%29\" to get \"40\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+-31+%29%29%2F%282%281%29%29\" Subtract \"40\" from \"9\" to get \"-31\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+sqrt%28+-31+%29%29%2F%282%29\" Multiply \"2\" and \"1\" to get \"2\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283+%2B-+i%2Asqrt%2831%29%29%2F%282%29\" Simplify the square root \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2Bi%2Asqrt%2831%29%29%2F%282%29\" or \"x+=+%283-i%2Asqrt%2831%29%29%2F%282%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "So the answers are \"x+=+%283%2Bi%2Asqrt%2831%29%29%2F%282%29\" or \"x+=+%283-i%2Asqrt%2831%29%29%2F%282%29\" \r
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\n" ); document.write( "\n" ); document.write( "# 2\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29=0\" Set the left side equal to zero\r
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\n" ); document.write( "\n" ); document.write( "Set each individual factor equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B8=0\", \"x-8=0\" or \"x%2B12=0\"\r
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\n" ); document.write( "\n" ); document.write( "Solve for x in each case:\r
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\n" ); document.write( "\n" ); document.write( "\"x=-8\", \"x=8\" or \"x=-12\"\r
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\n" ); document.write( "\n" ); document.write( "So our critical values are \"x=-8\", \"x=8\" and \"x=-12\"\r
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\n" ); document.write( "\n" ); document.write( "Now set up a number line and plot the critical values on the number line\r
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\n" ); document.write( "\n" ); document.write( "\"number_line%28+600%2C+-15%2C+10%2C-8%2C8%2C-12%29\"\r
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\n" ); document.write( "\n" ); document.write( "So let's pick some test points that are near the critical values and evaluate them.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is less than \"-12\" (notice how it's to the left of the leftmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-13\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-13%2B8%29%28-13-8%29%28-13%2B12%29%3E+0\" Plug in \"x=-13\"\r
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\n" ); document.write( "\n" ); document.write( "\"-105%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-12\" and \"-8\":\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%28-10%2B8%29%28-10-8%29%28-10%2B12%29%3E+0\" Plug in \"x=-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"72%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is in between \"-8\" and \"8\":\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%280%2B8%29%280-8%29%280%2B12%29%3E+0\" Plug in \"x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"-768%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is false, this means that the interval does not work. So this interval is not in our solution set and we can ignore it.\r
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\n" ); document.write( "\n" ); document.write( "Let's pick a test value that is greater than \"8\" (notice how it's to the right of the rightmost endpoint):\r
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\n" ); document.write( "\n" ); document.write( "So let's pick \"x=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-8%29%28x%2B12%29%3E0\" Start with the given inequality\r
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\n" ); document.write( "\n" ); document.write( "\"%289%2B8%29%289-8%29%289%2B12%29%3E+0\" Plug in \"x=9\"\r
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\n" ); document.write( "\n" ); document.write( "\"357%3E+0\" Evaluate and simplify the left side\r
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\n" ); document.write( "\n" ); document.write( "Since the inequality is true, this means that the interval works. So this tells us that this interval is in our solution set.\r
\n" ); document.write( "\n" ); document.write( " So part our solution in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Summary:\r
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\n" ); document.write( "\n" ); document.write( "So the solution in interval notation is:\r
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\n" ); document.write( "\n" ); document.write( "# 3\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-5x%2B1\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28-4%29%5E2-5%28-4%29%2B1\" Plug in \"x=-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%2816%29-5%28-4%29%2B1\" Square \"-4\" to get \"16\".\r
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\n" ); document.write( "\n" ); document.write( "\"32-5%28-4%29%2B1\" Multiply \"2\" and \"16\" to get \"32\".\r
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\n" ); document.write( "\n" ); document.write( "\"32%2B20%2B1\" Multiply \"-5\" and \"-4\" to get \"20\".\r
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\n" ); document.write( "\n" ); document.write( "\"53\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2-5x%2B1=53\" when \"x=-4\"\r
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\n" ); document.write( "\n" ); document.write( "# 4\r
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\n" ); document.write( "\n" ); document.write( "\"%289x%5E8-3%29%28x%5E9-3%29\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%289x%5E8%29-3%29%28highlight%28x%5E9%29-3%29\" Multiply the First terms:\"%289%2Ax%5E8%29%2A%28x%5E9%29=9%2Ax%5E17\". Note: simply add the exponents\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%289x%5E8%29-3%29%28x%5E9%2Bhighlight%28-3%29%29\" Multiply the Outer terms:\"%289%2Ax%5E8%29%2A%28-3%29=-27%2Ax%5E8\".\r
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\n" ); document.write( "\n" ); document.write( "\"%289x%5E8%2Bhighlight%28-3%29%29%28highlight%28x%5E9%29-3%29\" Multiply the Inner terms:\"%28-3%29%2A%28x%5E9%29=-3%2Ax%5E9\".\r
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\n" ); document.write( "\n" ); document.write( "\"%289x%5E8%2Bhighlight%28-3%29%29%28x%5E9%2Bhighlight%28-3%29%29\" Multiply the Last terms:\"%28-3%29%2A%28-3%29=9\".\r
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\n" ); document.write( "\n" ); document.write( "So we have the terms: \"9%2Ax%5E17\", \"-27%2Ax%5E8\", \"-3%2Ax%5E9\", \"9\" \r
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\n" ); document.write( "\n" ); document.write( "\"9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9\" Now add every term listed above to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "So \"%289x%5E8-3%29%28x%5E9-3%29\" FOILs to \"9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"%289x%5E8-3%29%28x%5E9-3%29=9%2Ax%5E17-27%2Ax%5E8-3%2Ax%5E9%2B9\".
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