document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27161>Question 27161</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eleven years ago Lynn was four times as old as her brother. In one year she will<BR>\n" );
document.write( "be twice as old as he is now. What are their ages now?<BR>\n" );
document.write( "How do I write the formula? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14759 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 11 years ago<BR>\n" );
document.write( "Her bro = x<BR>\n" );
document.write( "Her = 4x<BR>\n" );
document.write( "In one year = x+1<BR>\n" );
document.write( "and 4x+1\r<BR>\n" );
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document.write( "twice as old as he is:<BR>\n" );
document.write( "2(x+1)=4x+1<BR>\n" );
document.write( "2x+2=4x+1<BR>\n" );
document.write( "-2x=-1<BR>\n" );
document.write( "x=0.5\r<BR>\n" );
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document.write( "4(0.5)=2\r<BR>\n" );
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document.write( "Hence, Lynn is 2 years old and her brother is half a years old.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );