document.write( "Question 196819: Hello!\r
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\n" ); document.write( "\n" ); document.write( "A large pond is stocked with fish. The fish population P is modeled by the formula P = 4t + 8√t + 110, where t is the number of days since the fish were first introduced into the pond. How many days will it take for the fish population to reach 500?\r
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Algebra.Com's Answer #147549 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Is the given equation \"P=4t%2Bsqrt%28t%2B110%29\" ???\r
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\n" ); document.write( "\n" ); document.write( "\"P=4t%2Bsqrt%28t%2B110%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"500=4t%2Bsqrt%28t%2B110%29\" Plug in \"P=500\"\r
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\n" ); document.write( "\n" ); document.write( "\"500-4t=sqrt%28t%2B110%29\" Subtract 4t from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%28500-4t%29%5E2=%28sqrt%28t%2B110%29%29%5E2\" Square both sides\r
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\n" ); document.write( "\n" ); document.write( "\"%28500-4t%29%5E2=t%2B110\" Square the square root to eliminate it.\r
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\n" ); document.write( "\n" ); document.write( "\"250000-4000t%2B16t%5E2=t%2B110\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"250000-4000t%2B16t%5E2-t-110=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"16t%5E2-4001t%2B249890=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"At%5E2%2BBt%2BC\" where \"A=16\", \"B=-4001\", and \"C=249890\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for t\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( " Plug in \"A=16\", \"B=-4001\", and \"C=249890\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+sqrt%28+%28-4001%29%5E2-4%2816%29%28249890%29+%29%29%2F%282%2816%29%29\" Negate \"-4001\" to get \"4001\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+sqrt%28+16008001-4%2816%29%28249890%29+%29%29%2F%282%2816%29%29\" Square \"-4001\" to get \"16008001\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+sqrt%28+16008001-15992960+%29%29%2F%282%2816%29%29\" Multiply \"4%2816%29%28249890%29\" to get \"15992960\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+sqrt%28+15041+%29%29%2F%282%2816%29%29\" Subtract \"15992960\" from \"16008001\" to get \"15041\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+sqrt%28+15041+%29%29%2F%2832%29\" Multiply \"2\" and \"16\" to get \"32\". \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001+%2B-+13%2Asqrt%2889%29%29%2F%2832%29\" Simplify the square root (note: If you need help with simplifying square roots, check out this solver) \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%284001%2B13%2Asqrt%2889%29%29%2F%2832%29\" or \"t+=+%284001-13%2Asqrt%2889%29%29%2F%2832%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"t=128.864\" or \"t=121.199\" Use a calculator to approximate\r
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\n" ); document.write( "\n" ); document.write( "Now because plugging in \"t=128.864\" back in the second equation results in a contradiction, this means that \"t=128.864\" is NOT a solution.\r
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\n" ); document.write( "\n" ); document.write( "So the only solution is approximately \"t=121.199\"\r
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\n" ); document.write( "\n" ); document.write( "This means that it will take about 122 days (rounding up to the nearest whole number) for the fish population to reach 500.
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