document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196798>Question 196798</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 90 ft^2. The length is 3 more than twice the width. What are the demensions of the rectangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147528 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Garamond\" size=\"+2\">\r<BR>\n" );
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document.write( "Let <b><i>x</i></b> represent the width of the rectangle.  Then the length of the rectangle must be <b>2<i>x</i> + 3</b>.  Since the area of a rectangle is length times width:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x(2x + 3) = 90\">\r<BR>\n" );
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document.write( "so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 2x^2 + 3x - 90 = 0\">\r<BR>\n" );
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document.write( "Solve the quadratic. Hint: It factors rather tidily.  Exclude the negative root because you are looking for a positive measure of length.  The positive root will give you the width and the length follows from the given relationship between length and width.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
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