document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196753>Question 196753</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing the square:<BR>\n" );
document.write( "     x^2 + 8x + 13 = 0<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147470 by </B><A HREF=/tutors/aboutme.mpl?userid=J2R2R><B>J2R2R(94)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=J2R2R><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=J2R2R><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147470\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Completing the square requires half the coefficient of x to be used (when the coefficient of x^2 is 1) so that we have a square on one side and since this isn’t 0 generally we have it equal to whatever we have to adjust the equation to which is 3 in this example.\r<BR>\n" );
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document.write( "(x + 4)^2 = x^2 + 8x + 16 so\r<BR>\n" );
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document.write( "x^2 + 8x + 13 = (x^2 + 8x + 16) - 3 = 0\r<BR>\n" );
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document.write( "(x + 4)^2 - 3 = 0\r<BR>\n" );
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document.write( "(x + 4)^2 = 3\r<BR>\n" );
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document.write( "Therefore\r<BR>\n" );
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document.write( "x + 4 = + or - square root of 3\r<BR>\n" );
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document.write( "x = - 4 + or - square root of 3 </SPAN>\n" );
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