document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196749>Question 196749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you help me simplify x^2+7x+12/x-5 * 2x-10/x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147466 by </B><A HREF=/tutors/aboutme.mpl?userid=naivemind><B>naivemind(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=naivemind><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x^2+7x+12)/(x-5)*(2x-10)/(x+3)    expand the numerator for (x^2+7x+12)=(x+3)(x+4)\r<BR>\n" );
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document.write( "= ((x+3)(x+4))/(x-5)*2(x-5)/(x-3)  factor a 2 from (2x-10)= 2(x-5)\r<BR>\n" );
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document.write( "now we see that (x+3) and (x-5) cancel out leaving us with = 2(x+4) = 2x+8\r<BR>\n" );
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