document.write( "Question 196715: Find the smallest of three consecutive positive integers such that the product of the two smaller integers is 2 more than twice the largest integer.(an algebric solution can be accepted.) \n" ); document.write( "
Algebra.Com's Answer #147435 by ankor@dixie-net.com(22740)\"\" \"About 
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Find the smallest of three consecutive positive integers such that the product
\n" ); document.write( " of the two smaller integers is 2 more than twice the largest integer.
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\n" ); document.write( "three consecutive positive integers:
\n" ); document.write( "x, x+1, x+2
\n" ); document.write( ":
\n" ); document.write( "\"the product of the two smaller integers is 2 more than twice the largest integer.
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\n" ); document.write( "x(x+1) = 2(x+2) + 2
\n" ); document.write( "x^2 + x = 2x + 4 + 2
\n" ); document.write( "x^2 + x = 2x + 6
\n" ); document.write( "Arrange as a quadratic equation
\n" ); document.write( "x^2 + x - 2x - 6 = 0
\n" ); document.write( "x^2 - x - 6 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(x-3)(x+2) = 0
\n" ); document.write( "x = 3 is the positive solution
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\n" ); document.write( "The numbers are 3, 4, 5
\n" ); document.write( "Check solution in the statement:
\n" ); document.write( "the product of the two smaller integers is 2 more than twice the largest integer.
\n" ); document.write( "3*4 = 2(5) + 2
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