document.write( "Question 196696: Identify the conic section represented by each equation. For a poraola, give the vertex. For a circle, give the center and radius. For an ellipse or hyperbola, give the center and foci.\r
\n" ); document.write( "\n" ); document.write( "(1) x^2-4y^2+4x+8y-16=0
\n" ); document.write( "For this one I found that the equation would be (x+2)^2/16-(y-1)^2/4=1
\n" ); document.write( "I got that this is a hyperbola.
\n" ); document.write( "I found the center to be (-2,1)
\n" ); document.write( "I found the foci to be (4.47,0) (-4.47,0).\r
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\n" ); document.write( "\n" ); document.write( "(2) 25x^2+4y^2-50x-24y-39=0
\n" ); document.write( "For this one I found that the equation would be (x-1)^2/4 + (y-3)^2/25=1
\n" ); document.write( "I got that this is an ellipse
\n" ); document.write( "I found that the center is (1,3)
\n" ); document.write( "I found that the foci is (0,4.58) (0,-4.58)\r
\n" ); document.write( "\n" ); document.write( "Is this correct?
\n" ); document.write( "I'm not really sure what I'm doing....\r
\n" ); document.write( "\n" ); document.write( "Thank you!!
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Algebra.Com's Answer #147430 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
(1) x^2-4y^2+4x+8y-16=0
\n" ); document.write( "For this one I found that the equation would be (x+2)^2/16-(y-1)^2/4=1
\n" ); document.write( "I got that this is a hyperbola.
\n" ); document.write( "I found the center to be (-2,1)
\n" ); document.write( "I found the foci to be (4.47,0) (-4.47,0)
\n" ); document.write( "The center is correct, but the foci can't be symmetrical about the Origin if the center is not at the Origin.
\n" ); document.write( "You have to add the \"offset\" to the foci, that is, shift them in the same way the center is shifted from the Origin.
\n" ); document.write( "foci at: (2.47,1) (-6.47,1)
\n" ); document.write( "---------------------------------
\n" ); document.write( "(2) 25x^2+4y^2-50x-24y-39=0
\n" ); document.write( "For this one I found that the equation would be (x-1)^2/4 + (y-3)^2/25=1
\n" ); document.write( "I got that this is an ellipse
\n" ); document.write( "I found that the center is (1,3)
\n" ); document.write( "I found that the foci is (0,4.58) (0,-4.58)
\n" ); document.write( "--------------
\n" ); document.write( "Same as above.
\n" ); document.write( "You have to add the \"offset\" to the foci, that is, shift them in the same way the center is shifted from the Origin.
\n" ); document.write( "--> foci at (1,7.58) (1,-1.58)
\n" ); document.write( "--------------
\n" ); document.write( "PS You can dl FREE software to graph these at
\n" ); document.write( "www.padowan.dk.com/graph/
\n" ); document.write( "Use Function, Insert Relation for these
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