document.write( "Question 27110: Please can you solve the following equation for $\"0%3Cx%3C360\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"sin+x+cos+150+%2B+cos+x+sin+150+=+1%2F2+\"$ \r
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\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #14741 by venugopalramana(3286) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sin+x+cos+150+%2B+cos+x+sin+150+=+1%2F2+\"$
\n" ); document.write( "sin(x+150)=0.5
\n" ); document.write( "sin(90+60+x)=0.5
\n" ); document.write( "-cos(60+x)=0.5
\n" ); document.write( "cos(60+x)=-0.5
\n" ); document.write( "60+x=120 degrees...if you are taught general solutions then 60+x=2n(pi)+-(pi)/3
\n" ); document.write( "x=60 degrees....if you are taught general solutions then x=2n(pi)+-(pi)/3-(pi)/3
\n" ); document.write( "...........................................x=2n(pi)..or...2n(pi)-2(pi)/3\r
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