document.write( "Question 196664: The sides of a rectangle are x and x+6. The area of the rectangle is 55. Find the lenghts of the sides.(an algebraic solution will be accepted.) \n" ); document.write( "

Algebra.Com's Answer #147396 by vleith(2983) $\"\"$ $\"About$

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$\"AreaOfRectangle+=+Lenght%2AWidth\"$
\n" ); document.write( " $\"55+=+x+%2A+%28x%2B6%29\"$
\n" ); document.write( " $\"55+=+x%5E2+%2B+6x\"$
\n" ); document.write( " $\"0+=+x%5E2+%2B+6x+-+55\"$
\n" ); document.write( " $\"0+=+%28x%2B11%29%28x-5%29\"$
\n" ); document.write( "x = -11 or 5
\n" ); document.write( "Since a side cannot be negative, x = 5
\n" ); document.write( "Then x+6 = 11\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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