document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196625>Question 196625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log subscript 8 square root 80 - log subscript 8 square root 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147385 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147385\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> subtracting logs means dividing their arguments\r<BR>\n" );
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document.write( "log subscript 8 [(square root 80)/(square root 5)]\r<BR>\n" );
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document.write( "log subscript 8 [square root (80/5)]\r<BR>\n" );
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document.write( "log subscript 8 [square root (16)]\r<BR>\n" );
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document.write( "log subscript 8 (4)\r<BR>\n" );
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document.write( "4 is 2^2 and 8 is 2^3 ___ so 4 = 8^(2/3)\r<BR>\n" );
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document.write( "log subscript 8 (4) = 2/3 </SPAN>\n" );
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