document.write( "Question 27112: In Paul's bank, there is $2.60 in pennies, nickels, and dimes. In all there are 45 coins. If there are twice as many nickels as pennies, find how many of each kind there are.
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Algebra.Com's Answer #14737 by Paul(988)\"\" \"About 
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Let the pennies be x
\n" ); document.write( "Let the nickels be 2x
\n" ); document.write( "Let the dimes be y\r
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\n" ); document.write( "\n" ); document.write( "so:
\n" ); document.write( "x+2x+y=45 comin total solve for y
\n" ); document.write( "y=45-3x (subsitution)\r
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\n" ); document.write( "\n" ); document.write( "Nickels value = 5
\n" ); document.write( "Dime value = 10
\n" ); document.write( "Pennie value = 1
\n" ); document.write( "Total value = 260\r
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\n" ); document.write( "\n" ); document.write( "5(2x)+10(y)+x=260 (subsitute for y)
\n" ); document.write( "10x+10(45-3x)+x=260
\n" ); document.write( "10x+450-30x+x=260\r
\n" ); document.write( "\n" ); document.write( "-19x=-190
\n" ); document.write( "x=10\r
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\n" ); document.write( "\n" ); document.write( "2(10)=20
\n" ); document.write( "y=45-3(10)
\n" ); document.write( "y=45-30
\n" ); document.write( "y=15\r
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\n" ); document.write( "\n" ); document.write( "Hence, there were 10 pennies, 20 nickels and 15 dimes.
\n" ); document.write( "Paul.
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