document.write( "Question 196612: Solve algebraically and check your potential solutions: √(x+2)-x=0 \n" ); document.write( "
Algebra.Com's Answer #147361 by stanbon(75887)\"\" \"About 
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\n" ); document.write( "Solve algebraically and check your potential solutions: √(x+2)-x=0
\n" ); document.write( "---
\n" ); document.write( "Rearrange:
\n" ); document.write( "sqrt(x+2) = x
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x+2 = x^2
\n" ); document.write( "x^2-x-2 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "(x-2)(x+1) = 0
\n" ); document.write( "x = 2 or x = -1
\n" ); document.write( "------
\n" ); document.write( "Check x = 2 in the original equation:
\n" ); document.write( "sqrt(2+2) = 2
\n" ); document.write( "That is true
\n" ); document.write( "--------
\n" ); document.write( "Check x = -1 in the original equation:
\n" ); document.write( "sqrt(-1+2) = -1
\n" ); document.write( "That is false
\n" ); document.write( "-------------------
\n" ); document.write( "Final Solution:
\n" ); document.write( "x = 2
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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