document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196240>Question 196240</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thrifty Parking Garage has 40 parking spaces. Each space can be used by a car or a motorcycle (no trucks). One day when all 40 spaces are in use, the owner walks through the garage and looks at each vehicle. He tells his assistant, \"There are 152 wheels in this garage right now.\" How many motorcycles are in the garage? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147356 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147356\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let c=number of cars and m=number of motorcycles.<BR>\n" );
document.write( "c+m=40<BR>\n" );
document.write( "4c+2m=152<BR>\n" );
document.write( "m=40-c<BR>\n" );
document.write( "4c+2(40-c)=152 substitute 40-c for m.<BR>\n" );
document.write( "4c+80-2c=152<BR>\n" );
document.write( "2c=72<BR>\n" );
document.write( "c=36<BR>\n" );
document.write( "m=4<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );