document.write( "Question 196582: Hi!\r
\n" ); document.write( "\n" ); document.write( "I'm having some difficulty with the following problem:\r
\n" ); document.write( "\n" ); document.write( "If F is the focal length of a convex lens and an object is placed at a distance x from the lens, then its image will be at a distance y from the lens, where F, x, and y are related by the lens equation below. Suppose that a lens has a focal length of 2.1 cm, and that the image of an object is 4 cm closer to the lens than the object itself. How far from the lens is the object?\r
\n" ); document.write( "\n" ); document.write( "1/F = 1/x + 1/y \r
\n" ); document.write( "\n" ); document.write( "thanks!
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Algebra.Com's Answer #147331 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Since \"the image of an object is 4 cm closer to the lens than the object itself\", this means that \"y=x-4\"\r
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\n" ); document.write( "\n" ); document.write( "\"1%2FF+=+1%2Fx+%2B+1%2Fy+\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F2.1+=+1%2Fx+%2B+1%2F%28x-4%29\" Plug in \"F=2.1\" and \"y=x-4\"\r
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\n" ); document.write( "\n" ); document.write( " Multiply EVERY term by the LCD \"2.1x%28x-4%29\" to clear out the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-4%29=2.1%28x-4%29%2B2.1x%281%29\" Cancel out and simplify\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x-4%29=2.1%28x-4%29%2B2.1x\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x=2.1x-8.4%2B2.1x\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"10x%5E2-40x=21x-84%2B21x\" Multiply EVERY term by 10 to make every number a whole number.\r
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\n" ); document.write( "\n" ); document.write( "\"10x%5E2-40x-21x%2B84-21x=0\" Get all terms to the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"10x%5E2-82x%2B84=0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic in the form of \"Ax%5E2%2BBx%2BC\" where \"A=10\", \"B=-82\", and \"C=84\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-B+%2B-+sqrt%28+B%5E2-4AC+%29%29%2F%282A%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-82%29+%2B-+sqrt%28+%28-82%29%5E2-4%2810%29%2884%29+%29%29%2F%282%2810%29%29\" Plug in \"A=10\", \"B=-82\", and \"C=84\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+sqrt%28+%28-82%29%5E2-4%2810%29%2884%29+%29%29%2F%282%2810%29%29\" Negate \"-82\" to get \"82\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+sqrt%28+6724-4%2810%29%2884%29+%29%29%2F%282%2810%29%29\" Square \"-82\" to get \"6724\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+sqrt%28+6724-3360+%29%29%2F%282%2810%29%29\" Multiply \"4%2810%29%2884%29\" to get \"3360\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+sqrt%28+3364+%29%29%2F%282%2810%29%29\" Subtract \"3360\" from \"6724\" to get \"3364\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+sqrt%28+3364+%29%29%2F%2820%29\" Multiply \"2\" and \"10\" to get \"20\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B-+58%29%2F%2820%29\" Take the square root of \"3364\" to get \"58\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2882+%2B+58%29%2F%2820%29\" or \"x+=+%2882+-+58%29%2F%2820%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28140%29%2F%2820%29\" or \"x+=++%2824%29%2F%2820%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+7\" or \"x+=+6%2F5\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So the possible answers are \"x+=+7\" or \"x+=+6%2F5\" \r
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\n" ); document.write( "\n" ); document.write( "However, since \"6%2F5-4=1.2-4=-2.8\" (which doesn't make much sense), this means we'll ignore \"x+=+6%2F5\"\r
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\n" ); document.write( "\n" ); document.write( "So the only answer is \"x+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the object is 7 cm from the lens.
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