document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27070>Question 27070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Judy is 3 times as old as Phyillis.  In 10 years, Judy will be twice as old as Phyllis.  Find their present age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14733 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can do it this way.<BR>\n" );
document.write( "Let J = Judy's present age and P = Phyllis's present age.\r<BR>\n" );
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document.write( "J = 3P and in 10 year's time:<BR>\n" );
document.write( "J+10 = 2(P+10)  Substitute the J = 3P from the first equation into the second equation and solve for P.\r<BR>\n" );
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document.write( "(3P)+10 = 2(P+10) Simplify.<BR>\n" );
document.write( "3P+10 = 2P+20 Subtract 2P from both sides.<BR>\n" );
document.write( "P+10 = 20 Subtract 10 from both sides.<BR>\n" );
document.write( "P = 10 and<BR>\n" );
document.write( "J = 3P = 3(10) = 30\r<BR>\n" );
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document.write( "Judy is 30 years old and Phyllis is 10 years old.<BR>\n" );
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