document.write( "Question 196576: Find two consecutive odd integers such that six times the first equals ten more than four times the second. \n" ); document.write( "
Algebra.Com's Answer #147308 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Let x & (x+2) be the 2 consecutive odd integers. \n" ); document.write( "6x=4(x+2)+10 \n" ); document.write( "6x=4x+8+10 \n" ); document.write( "6x-4x=18 \n" ); document.write( "2x=18 \n" ); document.write( "x=18/2 \n" ); document.write( "x=9 \n" ); document.write( "ans for the smaller integer. \n" ); document.write( "9+2=11 ans. for the next integer. \n" ); document.write( "Proof: \n" ); document.write( "6*9=4*11+10 \n" ); document.write( "54=44+10 \n" ); document.write( "54=54 \n" ); document.write( " |