document.write( "Question 196576: Find two consecutive odd integers such that six times the first equals ten more than four times the second. \n" ); document.write( "
Algebra.Com's Answer #147308 by checkley77(12844)\"\" \"About 
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Let x & (x+2) be the 2 consecutive odd integers.
\n" ); document.write( "6x=4(x+2)+10
\n" ); document.write( "6x=4x+8+10
\n" ); document.write( "6x-4x=18
\n" ); document.write( "2x=18
\n" ); document.write( "x=18/2
\n" ); document.write( "x=9
\n" ); document.write( "ans for the smaller integer.
\n" ); document.write( "9+2=11 ans. for the next integer.
\n" ); document.write( "Proof:
\n" ); document.write( "6*9=4*11+10
\n" ); document.write( "54=44+10
\n" ); document.write( "54=54
\n" ); document.write( "
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