document.write( "Question 196540: Solve by completing the square:
\n" ); document.write( " x^2 + 8x + 13 = 0
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Algebra.Com's Answer #147294 by josmiceli(19441)\"\" \"About 
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\"x%5E2+%2B+8x+%2B+13+=+0\"
\n" ); document.write( "\"x%5E2+%2B+8x+=+-13\"
\n" ); document.write( "\"x%5E2+%2B+8x+%2B+%288%2F2%29%5E2+=+-13+%2B+%288%2F2%29%5E2\"
\n" ); document.write( "\"x%5E2+%2B+8x+%2B+16+=+-13+%2B+16\"
\n" ); document.write( "The left side is a perfect square
\n" ); document.write( "\"%28x+%2B+4%29%5E2+=+3\"
\n" ); document.write( "Take the square root of both sides
\n" ); document.write( "\"x+%2B+4+=+sqrt%283%29\"
\n" ); document.write( "\"x+=+14+%2B+sqrt%283%29\"
\n" ); document.write( "and
\n" ); document.write( "\"x+%2B+4+=+-sqrt%283%29\"
\n" ); document.write( "\"x+=+-4+-+sqrt%283%29\"
\n" ); document.write( "I'll check the 2nd result
\n" ); document.write( "\"x%5E2+%2B+8x+%2B+13+=+0\"
\n" ); document.write( "\"%28-4+-+sqrt%283%29%29%5E2+%2B+8%2A%28-4+-sqrt%283%29%29+%2B+13+=+0\"
\n" ); document.write( "\"16+%2B+8%2Asqrt%283%29+%2B+3+-+32+-+8%2Asqrt%283%29+%2B+13+=+0\"
\n" ); document.write( "\"16+%2B+3+-+32+%2B+13+=+0\"
\n" ); document.write( "\"0+=+0\"
\n" ); document.write( "OK
\n" ); document.write( "
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