document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196512>Question 196512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two complementary angles are in the ratio of 1:4. Find the meaure of the smaller angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147284 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+4x=90<BR>\n" );
document.write( "5x=90<BR>\n" );
document.write( "x=90/5<BR>\n" );
document.write( "x=18 degrees for the smaller angle.<BR>\n" );
document.write( "4*18=72 degrees for the larger angle.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "18+72=90<BR>\n" );
document.write( "90=90 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );