document.write( "Question 196396: mary travels 45 miles up stream in 3 hours and travels 100 miles downstream in 4 hours. find the average speed of the boat in still water and the average speed of the current? \n" ); document.write( "
Algebra.Com's Answer #147238 by nerdybill(7384) You can put this solution on YOUR website! mary travels 45 miles up stream in 3 hours and travels 100 miles downstream in 4 hours. find the average speed of the boat in still water and the average speed of the current? \n" ); document.write( ". \n" ); document.write( "Applying the distance formula: \n" ); document.write( "d = rt \n" ); document.write( "where \n" ); document.write( "d is distance \n" ); document.write( "r is rate or speed \n" ); document.write( "t is time \n" ); document.write( ". \n" ); document.write( "Let x = speed of boat in still water \n" ); document.write( "and y = speed of current \n" ); document.write( ". \n" ); document.write( "Upstream: \n" ); document.write( "3(x-y)= 45 \n" ); document.write( "dividing both sides by 3: \n" ); document.write( "x - y = 15 \n" ); document.write( ". \n" ); document.write( "Downstream: \n" ); document.write( "4(x+y)= 100 \n" ); document.write( "dividing both sides by 4: \n" ); document.write( "x + y = 25 \n" ); document.write( ". \n" ); document.write( "Our system of equations: \n" ); document.write( "x - y = 15 (equation 1) \n" ); document.write( "x + y = 25 (equation 2) \n" ); document.write( ". \n" ); document.write( "Adding the two equations: \n" ); document.write( "x - y = 15 \n" ); document.write( "x + y = 25 \n" ); document.write( "----------- \n" ); document.write( "2x = 40 \n" ); document.write( "x = 20 mph (speed of boat in still waters) \n" ); document.write( ". \n" ); document.write( "substitute the above into equation 2 and solve for y: \n" ); document.write( "x + y = 25 \n" ); document.write( "20 + y = 25 \n" ); document.write( "y = 5 mph (speed of current) \n" ); document.write( " |