document.write( "Question 27027: Solve the system by addition or substitution.\r
\n" ); document.write( "\n" ); document.write( "3x + 6y = 0
\n" ); document.write( "x=2/3\r
\n" ); document.write( "\n" ); document.write( "Please help.\r
\n" ); document.write( "\n" ); document.write( "Thanks you so much.
\n" ); document.write( "

Algebra.Com's Answer #14719 by mbarugel(146)\"\" \"About 
You can put this solution on YOUR website!
If x = 2/3, then we can substitute this value into the first equation:\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+6y+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2A%282%2F3%29+%2B+6y+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"2+%2B+6y+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"6y+=+-2\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-2%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "The solution to this system is x=2/3 and y=-1/3
\n" ); document.write( "
\n" );