document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196334>Question 196334</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the numerator of a fraction is increased by 3, the fraction becomes 3/4. If the denominator is decreased by 7, the fraction becomes 1. Determine the original fraction. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147167 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n=numerator and d=denominator<BR>\n" );
document.write( "a) (n+3)/d=3/4<BR>\n" );
document.write( "b) n/(d+7)=1<BR>\n" );
document.write( "b) n=d+7<BR>\n" );
document.write( "a) (d+7+3)/d=3/4 substitute d+7 for n.<BR>\n" );
document.write( "a) (d+10)/d=3/4<BR>\n" );
document.write( "a) 4(d+10)=3d multiply each side by 4d<BR>\n" );
document.write( "a) 4d+40=3d<BR>\n" );
document.write( "d=-40<BR>\n" );
document.write( "b) n=-40+7<BR>\n" );
document.write( "n=-33<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );