document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26991>Question 26991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The line given by the equation y = 2x + 1/3 is perpendicular to the line given by what equation? <BR>\n" );
document.write( " <BR>\n" );
document.write( "   <BR>\n" );
document.write( " <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14716 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14716\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The line given by the equation y = 2x + 1/3 is perpendicular to the line given by what equation? <BR>\n" );
document.write( " <BR>\n" );
document.write( "THE PERPENDICULAR LINE'S EQN.IS <BR>\n" );
document.write( "2Y=-X+K...EXCHANGE X AND Y CORDINATES AND CHANGE SIGN OF ONE OF THEM IS THE RULR...<BR>\n" );
document.write( "THIS IS BECAUSE PRODUCT OF SLOPES SHOULD EQUAL -1 FOR 2 LINES TO BE PERPENDICULAR...IN THE ABOVE CASE WE GET<BR>\n" );
document.write( "(2)*(-1/2)=-1...HENCE THEY ARE PERPENDICULAR...K CAN BE ANY VALUE...TO FIND K YOU NEED ANOTHER CONDITION. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );