document.write( "Question 196268: find all rational zeros of p(x)= x^3-12x-16 \n" ); document.write( "
Algebra.Com's Answer #147115 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
p(x)= x^3-12x-16
\n" ); document.write( "I graphed it and found a zero at x = 4
\n" ); document.write( "---
\n" ); document.write( "Then, using synthetic division, I got the following:
\n" ); document.write( "---
\n" ); document.write( "4)....1....0....-12....-16
\n" ); document.write( ".......1....4.....4...|..0\r
\n" ); document.write( "\n" ); document.write( "Quotient: x^2 + 4x + 4 =0
\n" ); document.write( "Factors as (x+2)^2 = 0\r
\n" ); document.write( "\n" ); document.write( "==============================
\n" ); document.write( "Real Zeroes: x = 4, x = -2 with multiplicity 2
\n" ); document.write( "=====================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );