document.write( "Question 196272: A solution containing 30% insecticide is to be mixed with a solution of 50% insecticide to make a 200L solution containing 42% insecticide. How much of solutoin is used \n" ); document.write( "

Algebra.Com's Answer #147111 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let x represent the amount of 30% solution, then 200- x is the amount of 50% solution.\r
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\n" ); document.write( "\n" ); document.write( "So .3x is the amount of pure insecticide in the 30% solution, .5(200- x) is the amount pure insecticide in the 50% solution, and .42(200) is the amount of pure insecticide in the mixture, so:\r
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\n" ); document.write( "\n" ); document.write( "Solve for x\r
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