document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196218>Question 196218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello.\r<BR>\n" );
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document.write( "I'm having some difficulty figuring out the following word problem, Can you help me?\r<BR>\n" );
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document.write( "A jeweler has 6 rings, each weighing 7 g, made of an alloy of 5% silver and 95% gold. He decides to melt down the rings and add enough silver to reduce the gold content to 87%. How much silver should he add?\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147102 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147102\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the jeweler has 42g of alloy (6 times 7)\r<BR>\n" );
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document.write( "if the new alloy is 87% gold, then it is also 13% silver (87+13=100)\r<BR>\n" );
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document.write( "let x=\"amount of added silver\"\r<BR>\n" );
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document.write( "the original amount of silver plus the added silver equals the new amount<BR>\n" );
document.write( "___ (5%)(42) + x = (13%)(42+x)\r<BR>\n" );
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document.write( "2.1 + x = 5.46 + .13x\r<BR>\n" );
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document.write( ".87x = 3.36\r<BR>\n" );
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document.write( "x = 3.86 (approx) </SPAN>\n" );
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