document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196230>Question 196230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The track team ran to the cemetary at 8mph and jogged back home at 6mph. If the total trip took 7 hours, how far was it to the cemetary? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #147093 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=147093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> t = d/r (time = distance/rate)<BR>\n" );
document.write( "The distance to and from the cemetery (no a in cemetery) is obviously the same.<BR>\n" );
document.write( "7 = d/8 + d/6<BR>\n" );
document.write( "Multiply by 48<BR>\n" );
document.write( "336 = 6d + 8d = 14d<BR>\n" );
document.write( "d = 24 miles </SPAN>\n" );
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