document.write( "Question 196177: 3x + y = -5
\n" ); document.write( "x - 2y = 3
\n" ); document.write( "

Algebra.Com's Answer #147058 by anantha(86)\"\" \"About 
You can put this solution on YOUR website!
sol:
\n" ); document.write( "3x+y= -5
\n" ); document.write( "subtract 3x on both sides
\n" ); document.write( "3x+y-3x= -5-3x
\n" ); document.write( "y= -5-3x
\n" ); document.write( "substitute this value in x-2y=3
\n" ); document.write( "x-2*(-5-3x)=3
\n" ); document.write( "x-(2*-5-2*3x)=3
\n" ); document.write( "x-(-10-6x)=3
\n" ); document.write( "x+10+6x=3
\n" ); document.write( "7x+10=3
\n" ); document.write( "subtract 10 on both sides
\n" ); document.write( "7x+10-10=3-10
\n" ); document.write( "7x=-7
\n" ); document.write( "dividing by 7 on both sides
\n" ); document.write( "7x/7= -7/7
\n" ); document.write( "x=-1
\n" ); document.write( "substitute this value in 3x+y=-5
\n" ); document.write( "3*(-1)+y=-5
\n" ); document.write( "-3+y=-5
\n" ); document.write( "ading 3 on both sides
\n" ); document.write( "-3+y+3=-5+3
\n" ); document.write( "y= -2
\n" ); document.write( "
\n" ); document.write( "
\n" );