document.write( "Question 196119: The perimeter of a rectangle is 36. The lenght is 3 less than twice the width. Find the width. \n" ); document.write( "

Algebra.Com's Answer #147055 by anantha(86) $\"\"$ $\"About$

You can put this solution on YOUR website!
sol:
\n" ); document.write( " let width be x
\n" ); document.write( "twice the width is 2x
\n" ); document.write( "according to the problem
\n" ); document.write( "length= 3 less than twice the width
\n" ); document.write( "length=twice the width-3
\n" ); document.write( "length=2x-3
\n" ); document.write( "width=x
\n" ); document.write( "perimeter of the rectangle=2(length+bredth)
\n" ); document.write( "perimeter of the rectangle=2(2x-3+x)
\n" ); document.write( "perimeter of the rectangle=2(3x-3)
\n" ); document.write( "perimeter of the rectangle=6x-6
\n" ); document.write( "according to the problem
\n" ); document.write( "perimeter of the rectangle =36
\n" ); document.write( "6x-6=36
\n" ); document.write( "adding 6 on both sides
\n" ); document.write( "6x-6+6=36+6
\n" ); document.write( "6x=42
\n" ); document.write( "dividing by 6 on both sides
\n" ); document.write( "6x/6=42/6
\n" ); document.write( "x=7
\n" ); document.write( "width=7
\n" ); document.write( "length=2x-3
\n" ); document.write( "length=2*7-3
\n" ); document.write( "length=14-3=11 \n" ); document.write( "

\n" );