document.write( "Question 196178: x + 3y = 7
\n" ); document.write( "-x + y = -3 \n" ); document.write( "
Algebra.Com's Answer #147052 by nerdybill(7384)\"\" \"About 
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Solve using the addition method:
\n" ); document.write( "x + 3y = 7
\n" ); document.write( "-x + y = -3
\n" ); document.write( ".
\n" ); document.write( "Add both equations together:
\n" ); document.write( "x + 3y = 7
\n" ); document.write( "-x + y = -3
\n" ); document.write( "------------
\n" ); document.write( " 4y = 4
\n" ); document.write( "divide both sides by 4:
\n" ); document.write( " y = 1
\n" ); document.write( ".
\n" ); document.write( "Substitute the above into:
\n" ); document.write( "x + 3y = 7
\n" ); document.write( "And solve for 'x':
\n" ); document.write( "x + 3(1) = 7
\n" ); document.write( "x + 3 = 7
\n" ); document.write( "x = 4
\n" ); document.write( ".
\n" ); document.write( "Answer:
\n" ); document.write( "(x,y) = (4,1)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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