document.write( "Question 196127: The vertex and the axis of symmetry of the graph of y=x^2+5 are \n" ); document.write( "

Algebra.Com's Answer #147020 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
If the equation has the form
\n" ); document.write( " $\"ax%5E2+%2B+bx+%2B+c\"$ , then the
\n" ); document.write( "vertex is where $\"x+=+-b%2F%282a%29\"$
\n" ); document.write( "In your equation, $\"y+=+x%5E2+%2B+5\"$ ,
\n" ); document.write( "there is no $\"x\"$ term and no $\"b\"$ ,
\n" ); document.write( "so $\"b=0\"$ and $\"-b%2F%282a%29+=+0\"$ ,
\n" ); document.write( " $\"x=0\"$ is the axis of symmetry
\n" ); document.write( "That is the y-axis.
\n" ); document.write( "I already know that $\"x=0\"$ is the
\n" ); document.write( "x-coordinate of the vertex. What is
\n" ); document.write( "the y-coordinate?
\n" ); document.write( " $\"y+=+x%5E2+%2B+5\"$
\n" ); document.write( " $\"y+=+0+%2B+5\"$
\n" ); document.write( " $\"y+=+5\"$
\n" ); document.write( "So, the vertex is at (0,5)
\n" ); document.write( "I'll graph it, too
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-2%2C+10%2C+x%5E2+%2B+5%29+\"$ \n" ); document.write( "

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