document.write( "Question 196107: Lee is 7 years older than phil. 11 years ago Lee was twice as old as phil was then. find their ages now \n" ); document.write( "

Algebra.Com's Answer #147011 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"x\"$ = Lee's age now
\n" ); document.write( "Then $\"x+-+7\"$ = Phil's age now
\n" ); document.write( " $\"x+-+11\"$ = Lee's age $\"11\"$ years ago
\n" ); document.write( " $\"x+-+7+-+11\"$ = Phil's age $\"11\"$ years ago
\n" ); document.write( " $\"x+-+11+=+2%2A%28x+-+7+-+11%29\"$
\n" ); document.write( " $\"x+-+11+=+2x+-+14+-+22\"$
\n" ); document.write( " $\"-11+=+x+-+36\"$
\n" ); document.write( " $\"36+-+11+=+x\"$
\n" ); document.write( " $\"x+=+25\"$
\n" ); document.write( " $\"x+-+7+=+18\"$
\n" ); document.write( "Lee's age now is 25 and Phil's age now is 18
\n" ); document.write( "check answer:
\n" ); document.write( " $\"x+-+11+=+2%2A%28x+-+7+-+11%29\"$
\n" ); document.write( " $\"25+-+11+=+2%2A%2818+-+11%29\"$
\n" ); document.write( " $\"14+=+2%2A7\"$
\n" ); document.write( " $\"14+=+14\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );