document.write( "Question 196014: The Function 'f' is defined by f(x)=ax2+bx+c.Given that f(0)=6,f(-1)=15 and f(1)=1,find the values of a,b,c \n" ); document.write( "
Algebra.Com's Answer #146973 by dkala99(12)\"\" \"About 
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f(x)=ax^2+bx+c\r
\n" ); document.write( "\n" ); document.write( " f(0) = 6
\n" ); document.write( "a(0)^2+b(0)+c = 6
\n" ); document.write( " 0+0+c = 6
\n" ); document.write( " c = 6\r
\n" ); document.write( "\n" ); document.write( " f(-1) = 15
\n" ); document.write( "a(-1)^2+b(-1)+c = 15
\n" ); document.write( " a-b+c = 15
\n" ); document.write( " a-b+6 = 15
\n" ); document.write( " a-b = 15-6
\n" ); document.write( " a-b = 9 -----> equ 1\r
\n" ); document.write( "\n" ); document.write( " f(1) = 1
\n" ); document.write( " a(1)^2+b(1)+c = 1
\n" ); document.write( " a+b+c = 1
\n" ); document.write( " a+b+6 = 1
\n" ); document.write( " a+b = 1-6
\n" ); document.write( " a+b = -5 -----> equ 2 \r
\n" ); document.write( "\n" ); document.write( "solve equ 1 and 2\r
\n" ); document.write( "\n" ); document.write( " a-b = 9 (+)
\n" ); document.write( " a+b = -5
\n" ); document.write( " ---------
\n" ); document.write( " 2a = 4
\n" ); document.write( " a = 2
\n" ); document.write( "from equ 2
\n" ); document.write( "a+b = -5
\n" ); document.write( "2+b = -5
\n" ); document.write( " b = -5-2
\n" ); document.write( " b = -7\r
\n" ); document.write( "\n" ); document.write( "a = 2 ; b = -7 ; c = 6
\n" ); document.write( "-----------------------------------
\n" ); document.write( "check in f(1)=1\r
\n" ); document.write( "\n" ); document.write( "f(1) = 2(1)^2+(-7)(1)+6
\n" ); document.write( " = 2-7+6
\n" ); document.write( " f(1)= 1 \r
\n" ); document.write( "\n" ); document.write( "
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