document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=196019>Question 196019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6 inches less than three times its width. Find the dimensions of the rectangle if its area is 45 square inches. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146960 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area  =  Length * Width<BR>\n" );
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document.write( "BUT,,L= 3w-6,,,, given<BR>\n" );
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document.write( "A=l*w = (3w-6) * w = 3w^2 -6w = 45,,,given<BR>\n" );
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document.write( "3w^2 -6w -45  =0<BR>\n" );
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document.write( "3 (w^2 -2w -15) +0<BR>\n" );
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document.write( "Factoring<BR>\n" );
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document.write( "3(w+3)(w-5) = 0<BR>\n" );
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document.write( "using  Zero  Property<BR>\n" );
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document.write( "w+3 =0,,,,w = -3,,,not   realistic<BR>\n" );
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document.write( "W-5 = 0,  w=5,,,,ANSWER<BR>\n" );
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document.write( "Checking<BR>\n" );
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document.write( "w=5, L=3w-6 =3*5-6 = 15-6=9<BR>\n" );
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document.write( "A = l*w = 9*5 = 45 ,,,ok<BR>\n" );
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