document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=27019>Question 27019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on a mixture problem, I have tried to set the problem up, but these (percents) mess me up. How many oz. of an 8% alcohol solution must be mixed with a 12% alcohol sloution to obtain 100 oz. of a 12.2 alcohol solution?<BR>\n" );
document.write( "I think it is 12.2(100)-.08x = .12(100=x), but i can't get it to work out into an answer I have to chose from.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14696 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .08(S) + .12(100 - S) = .122 (100) = 12.2<BR>\n" );
document.write( "where S is the amount of 8% alcohol solution<BR>\n" );
document.write( ".08S + 12 - .12S = 12.2<BR>\n" );
document.write( "-.04S = .2<BR>\n" );
document.write( "S = -50<BR>\n" );
document.write( "I don't think the problem, as stated, has a solution<BR>\n" );
document.write( "when S = 0, then the left side is 12 (less than 12.2)<BR>\n" );
document.write( "when S = 100, the left side is 8 (also less than 12.2) </SPAN>\n" );
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