document.write( "Question 195993: mary is six years older than sue. in two years, mary will be twice as old as sue. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #146943 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Let x equals Sue's Age
\n" ); document.write( "Therefore, x+6 will be Mary's Age (6 yrs older)\r
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\n" ); document.write( "\n" ); document.write( "Condition: Two years hence, Mary's age will be twice as Sue:\r
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\n" ); document.write( "\n" ); document.write( "2(Sue+2yrs)=Mary+2yrs
\n" ); document.write( "\"red%282%29%28x%2Bred%282yrs%29%29=x%2B6%2Bred%282yrs%29\"
\n" ); document.write( "\"2x%2B4=x%2B8\"
\n" ); document.write( "Combine similar terms:
\n" ); document.write( "\"2x-x=8-4\"
\n" ); document.write( "\"red%28x=4yrs%29\", Sue's present age\r
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\n" ); document.write( "\n" ); document.write( "Then, \"x%2B6=4%2B6=red%2810yrs%29\", Mary's Present Age\r
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\n" ); document.write( "\n" ); document.write( "Check, (via condition)
\n" ); document.write( "\"2%284%2B2%29=10%2B2\"
\n" ); document.write( "\"2%286%29=12\"
\n" ); document.write( "\"12yrs=12yrs\"\r
\n" ); document.write( "\n" ); document.write( "*Note: In 2yrs, Sue will be 6 yrs old (4+2yrs), where Mary is twice as old, 12 yrs (10+2yrs).\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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