document.write( "Question 195993: mary is six years older than sue. in two years, mary will be twice as old as sue. find their present ages. \n" ); document.write( "
Algebra.Com's Answer #146943 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Let x equals Sue's Age \n" ); document.write( "Therefore, x+6 will be Mary's Age (6 yrs older)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Condition: Two years hence, Mary's age will be twice as Sue:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(Sue+2yrs)=Mary+2yrs \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Combine similar terms: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check, (via condition) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "*Note: In 2yrs, Sue will be 6 yrs old (4+2yrs), where Mary is twice as old, 12 yrs (10+2yrs).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " |