document.write( "Question 27025: write an equation for the line that is perpendicular to x/5 - 3y = 6 and passes through the point (-2,4). \n" ); document.write( "
Algebra.Com's Answer #14694 by josmiceli(19441)\"\" \"About 
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Here's what I get:
\n" ); document.write( "x/5 - 3y = 6
\n" ); document.write( "subtract x/5 from both sides
\n" ); document.write( "- 3y = -x/5 + 6
\n" ); document.write( "divide both sides by 3
\n" ); document.write( "-y = -x/15 + 2
\n" ); document.write( "multiply both sides by -1
\n" ); document.write( "y = x/15 + 2
\n" ); document.write( "this is in the form y = mx + b where m iis the slope
\n" ); document.write( "so m = 1/15
\n" ); document.write( "a line perpendicular to this one will have a slope of -1/m
\n" ); document.write( "where m = 1/15
\n" ); document.write( "-1/(1/15) = -15
\n" ); document.write( "so the equation that is per pendicular has the form
\n" ); document.write( "y = -15x + b
\n" ); document.write( "and goes through the point (-2, 4)
\n" ); document.write( "4 = -15 * (-2) + b
\n" ); document.write( "4 = 30 + b
\n" ); document.write( "subtract 30 from both sides
\n" ); document.write( "b = -26
\n" ); document.write( "so, I get y = 15x -26
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