document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=195925>Question 195925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 32 mph to vist a nearby town. The cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the town.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #146937 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=146937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A cyclist traveled at a rate of 32 mph to vist a nearby town. The cyclist averaged 10 mph on the return trip. If the round trip took 6.3 hours, find the distance to the town. <BR>\n" );
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document.write( "Let x = time it took to get to the town<BR>\n" );
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document.write( "6.3-x = time it took to return<BR>\n" );
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document.write( "Applying the distance formula: d = rt<BR>\n" );
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document.write( "32x = 10(6.3-x)<BR>\n" );
document.write( "32x = 63-10x<BR>\n" );
document.write( "42x = 63<BR>\n" );
document.write( "x = 63/42<BR>\n" );
document.write( "x = 1.5 hours<BR>\n" );
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document.write( "Distance to town:<BR>\n" );
document.write( "1.5(32) = 48 miles<BR>\n" );
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