document.write( "Question 195962: evaluate 2x-y if x=1/3 and y=3/5 \n" ); document.write( "
Algebra.Com's Answer #146927 by RAY100(1637)\"\" \"About 
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2x-y
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\n" ); document.write( "2(1/3) -(3/5)
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\n" ); document.write( "LCD =15
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\n" ); document.write( "10/15 -9/15
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\n" ); document.write( "1/15
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\n" ); document.write( ".667 - .6 =.067 = 1/15,,,ok
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